Monday, September 29, 2014

3 Ball Stress Calculator

Some people may have to make sure to allow/unblock ads to see the cdfs.  Additionally you may need to download the Wolfram CDF player.

This calculates the stress applied in a 3 point ball loading configuration according to the formula:

$$\sigma = \frac{-3}{4 \pi} P \frac{\left( X - Y \right)}{b^2}$$

where
$$X = (1+\nu) \ln \left( \frac{r_2}{r_3}\right)^2 + \frac{1-\nu}{2} \left( \frac{r_2}{r_3}\right)^2,$$
$$Y = (1+\nu) \left(1+\ln \left( \frac{r_1}{r_3}\right)^2 \right) + (1-\nu) \left( \frac{r_1}{r_3}\right)^2,$$
$P$ is the applied load in Newtons,
$r_1$ is the radius of the support circle in mm,
$r_2$ is the radius of the loaded area in mm,
$r_3$ is radius of the specimen in mm,
$b$ is the sample thickness in mm,
and $\nu$ is Poisson's ratio.

The radius of the support circle is, as far as I can tell, the radius of the circle produced by the points of the 3 balls supporting the sample.  The radius of the loaded area is the radius of the piston on top pressing down on the sample.  The radius of the specimen is the radius of the circular sample.  From what I can tell, $r_2 < r_1 < r_3$ by definition.

Thursday, October 24, 2013

Tetrahedral Structures ala Bit-Player

The wonderful blog entry found here by Brian Hayes at Bit-Player was inspirational and led me to an area that I had long thought barren! I recently got my son some of the Geomag sticks and ball bearings and playing with them I got the impression that they were fun, but the models that I could make were limited. Well I was SO wrong. In his blog entry Brian Hayes introduced me to the tetrahelix, but also issued an irresistible challenge concerning a bridge that he built. He said "The result (below) is no longer a helix at all but a weird sort of bridge with an arched spine and two zigzag rails. If you extend the arc further, will the two ends meet to form a closed loop? I don’t have enough Geomags to answer that question." I just couldn't resist. I modelled it on Mathematica and was eventually led to a notation for a chain of attached tetrahedrons. I started by labelling his original figure


I started with arbitrarily numbering the vertices of the tetrahedron on the end.  From this, I could specify the next tet by writing down the vertex that was reflected through the plane of the other three.  For example, in his picture above, 1 was reflected to 1'.  I continued this forward to get the sequence:

{1,4,3,2,4,1,3,4,2,1,4,3,2,4,1,3,4,2,1,4,3,2,4}

The great thing is this repeats!  The unit is {1,4,3,2,4,1,3,4,2}.  The natural questions now just flood in with this notation.  For example, I can do random walks using this sequence.  Also, I believe the fact that this structure curves is due to the over abundance of the number 4. For example, the unit {1,2,3,4} leads to the tetrahelix (as do all of the permutations of this unit) which makes me believe that there is definitely some deeper math going on here.  For example I believe an even permutation leads to a right-handed helix and an odd permutation leads to a left-handed helix.  Anyway, I found with 95 steps using the above unit, the ring comes close, but does not close as you can see below.

This made me wonder if any units can actually close after repeating.  I think not, but I haven't checked yet.  I imagine that if you are dealing with units, an integral multiple of the unit would have to match up with the full circle.  But then, you could meander away and then come back, or you could have a non-repeating number that closed on itself.

Anyway here is a short cdf where you can explore units up to 6. 

I have not worried about intersection, and if you relaxed the requirement that consecutive numbers aren't equal (this just flips a tet back to where it started) you can make any tetrahedral structure, you just label the tetrahedra sequentially. When you get to the end of a limb, you reflect the sequence till you get back to the main line.  This is not the best way of doing things, but it seems to be complete.  Anyway, many more things to explore!  I think I have to invest in a few more Geomag sets.

Tuesday, March 26, 2013

Effective Mass Surface of an Ellipsoid

Here are the ellipsoidal effective mass surfaces.

$E = E_0 \pm \frac{\hbar^2 k_{r}^2}{2 m_e} f(\theta, \phi)$

Friday, January 18, 2013

Tuesday, September 11, 2012

DFT of Geometric Matrices

Here we plot special matrices (where any element can only be 0,i,-1,-i, and 1) and the DFT of those matrices.  Click on a cell of the matrix to cycle through element values.  To change the color, select from the drop down box.  To select a larger size, find select the size then press "Reset".  The numerical value of the DFT gets annoying, so hide it by unchecking the checkbox.

Monday, September 10, 2012

Two-band Tight-Binding Band Plot z=0

Two-band tight-binding model with 3rd NN interactions

Thursday, August 9, 2012

Graphite Q Point

Here is a demonstration of the energy dispersion near the Q point of Graphite.


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